By 26/03/2014 8 Comments

Exercise Program # 02 Operators in C++

Q: Write a program that will solve for the power dissipation of a resistor when the voltage across the resistor and the current in the resistor are known. The relationship for the power dissipation is: P=I^2*R?

Answer:

#include <iostream.h>  
#include <conio.h>

void main()
{      
     float V, I, R, P;

     cout<<"Enter the voltage across the resistor: "; cin>>V;
     cout<<"Enter the current through the resistor: "; cin>>I;
     R=V/I;  
     P=(I*I)*R;
     cout<<"The power dissipation is "<<P<<" watts";

     getch();
}






Posted in: C++ Exercises

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